'get list of lists from dict of lists by grouping elements at same index in every key-value pair [duplicate]
I have a dictionary
a = {'a':[1,2,3],'b':[4,5,6]}
Now, I wish to convert it into a list of lists such that
[[1,4],[2,5],[3,6]]
i.e. the 1st element of every key-value pair grouped together, every 2nd element grouped together & likewise. Also, number of keys isn't restricted to 2 & can be 'n'
Solution 1:[1]
If you're fine with the results being tuples rather than lists an easy way is:
list(zip(*a.values()))
else sprinkling in some list comprehension can cast to the correct type:
[list(value_pair) for value_pair in zip(*a.values())]
Sources
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Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Xenatic |
