Function not giving normal output

Question

I am trying to compile my practice on functions. I tried many times to compile this and I bumped into this issue.

Here below is my code:

#include <stdio.h>
int displayFlow();
int main(){
    int displayFlow();
   
}
int displayFlow(){

int try1,try2,try3;
printf("enter any given number...\n");
scanf("%d", &try1);
printf("if u entered above 10, ur out\n...please enter another guess...\n");
scanf("%d", &try2);
printf("if u entered below 5 then u won! !");


}

and this is the output I got:

function.c:22:5: note: declared here
 int test(){

Answer 1

You declared your function again inside main. Remove int from infront of displayFlow.

#include <stdio.h>
int displayFlow();
int main(){
    displayFlow();

}
int displayFlow(){

int try1,try2,try3;
printf("enter any given number...\n");
scanf("%d", &try1);
printf("if u entered above 10, ur out\n...please enter another guess...\n");
scanf("%d", &try2);
printf("if u entered below 5 then u won! !");


}

Answer 2

I come up with another mistake:you define the function displayFlow as 'int' type,but you don't write 'return' in the function when you realize it.

#include <stdio.h>
int displayFlow();
int main(){
    displayFlow(); //you just abandon the return value?

}
int displayFlow(){

int try1,try2,try3;
printf("enter any given number...\n");
scanf("%d", &try1);
printf("if u entered above 10, ur out\n...please enter another guess...\n");
scanf("%d", &try2);
printf("if u entered below 5 then u won! !");
//Here is something absent. What do you want to return ? or you just want to return nothing? if so, you should modify the function return value type to 'void',please.
//return ??;
}

Answer 3

Just set return in method main, because he has to return int

int main() {
return displayFlow();

}