Filtering words containing certain characters from a list

Question

I have a list of words and a list of letters:

list = ["clyde","tool","ball","window"]
letters = ["c","t"]

I want to filter the first list by removing the word if it has any letters from the second list.

list = ["ball","window"]

Answer 1

You can use filter() and all() to only retain words that do not have any letters that appear in letters (as an aside, you shouldn't use list as a variable name, as it shadows the list builtin):

data = ["clyde","tool","ball","window"]
letters = ["c","t"]

result = list(filter(lambda x: all(c not in x for c in letters), data))

# Prints ['ball', 'window']
print(result)

Answer 2

Using set objects makes this pretty straight forward (and is the only solution so far which doesn't require iterating over the letters of each word using Python -- set.intersection() defers to the underlying C code to iterate over each letter):

words = ["clyde", "tool", "ball", "window"]
letters = {"c", "t"}  # a set object

filtered_words = [word for word in words if not letters.intersection(word)]

Answer 3

This problem can be solved using List Comprehensions?like this?

lst = ["clyde","tool","ball","window"]
letters = ["c","t"]

res = [data for data in lst if all(item not in data for item in letters)]
print(res)

Please note that it is better not to have variables with the same name as keywords in python,so I changed the list to lst

Answer 4

Simple to understand code example

words_list = ["clyde","tool","ball","actor","window"]
letters = ["c","t"]
final_list=[]
# loop for each word in main list
for word in words_list:
    #check for each letter if present in restricted letters
    for letter in word:
        if letter in letters:
            break
    else:
        final_list.append(word)

print(final_list)