Filter nested dictionaries to second time key name appears, python

Question

I would like to filter custom_fields1 so that the only remaining items are the ones who have 'Value' = 'Ja' below the line 'Name' = 'GPP' (and not below the first 'Name' key 'Name': 'Informationen'). Does anyone know how to efficiently filter through the dictionary? I am happy for every tip!

custom_fields1 = 
[(44,
  {'@odata.context': 'http://api.hellohq.io/v1/$metadata#CustomFields',
   'value': [{'Name': 'Informationen',
     'Value': '',
     'Type': 'TextMultiline',
     'Id': 18020,
     'CreatedBy': 0,
     'UpdatedBy': 0,
     'CreatedOn': None,
     'UpdatedOn': None},
    {'Name': 'GPP',
     'Value': 'Ja',
     'Type': 'DropdownCheckbox',
     'Id': 18049,
     'CreatedBy': 0,
     'UpdatedBy': 0,
     'CreatedOn': None,
     'UpdatedOn': None}]}),
 (45,
  {'@odata.context': 'http://api.hellohq.io/v1/$metadata#CustomFields',
   'value': [{'Name': 'Informationen',
     'Value': '',
     'Type': 'TextMultiline',
     'Id': 18020,
     'CreatedBy': 0,
     'UpdatedBy': 0,
     'CreatedOn': None,
     'UpdatedOn': None},
    {'Name': 'GPP',
     'Value': 'Ja',
     'Type': 'DropdownCheckbox',
     'Id': 18049,
     'CreatedBy': 0,
     'UpdatedBy': 0,
     'CreatedOn': None,
     'UpdatedOn': None}]}),
 (46,
  {'@odata.context': 'http://api.hellohq.io/v1/$metadata#CustomFields',
   'value': [{'Name': 'Informationen',
     'Value': '',
     'Type': 'TextMultiline',
     'Id': 18020,
     'CreatedBy': 0,
     'UpdatedBy': 0,
     'CreatedOn': None,
     'UpdatedOn': None},
    {'Name': 'GPP',
     'Value': 'Nein',
     'Type': 'DropdownCheckbox',
     'Id': 18049,
     'CreatedBy': 0,
     'UpdatedBy': 0,
     'CreatedOn': None,
     'UpdatedOn': None}]}))]
```

Answer 1

Your structure is sooo nested! Let's break it step by step.

• It's a list, so we want to iterate over it

for field in custom_field:
    <I have an element>

• What the element is? Its a tuple and second element is what interest me dict1 = field[1]
• Now I have a dictionary, where value is what interest me most values1 = dict['value']
• Oh, is it list again? Let's iterate again!

for dict_value in values1:
    <this is the dict I need!>

• I got proper dict, now I just need to check my conditions

def check(dict_value):
    return dict_value["name"] == ... and dict_value["Value"] == ...

How to do filtering based on that? You can use list filtering

[dict_value for dict_value in values1 if check(dict_value)]

And assign it to "value" key of outer dict.

Other option could be deleting records with del that does not satisfy our check.