'Extracting all nested IDs
I have below JSON for example where I need to extract all categories Id from the last subcategory if its not empty. For instance: On below JSON I need Ids like mens-apparel-ricky inside last categories object but if this categories was empty I like to extract the last ID like womens-new-arrivals. Basically it should be the list of all these ID's extracted.
Thanks in Advance
"categories": [{
"id": "featured",
"name": "NEW ARRIVALS",
"categories": [{
"id": "featured-new-arrivals",
"name": "New Arrivals",
"categories": [{
"id": "mens-new-arrivals",
"name": "Mens",
"categories": []
}, {
"id": "womens-new-arrivals",
"name": "Womens",
"categories": [{
"id": "mens-apparel-ricky",
"name": "Relaxed",
"categories": []
}, {
"id": "new-arrivals-kids",
"name": "Kids",
"categories": []
}, {
"id": "new-arrivals-accessories",
"name": "Accessories",
"categories": []
}]
}, {
"id": "collections",
"name": "Featured",
"categories": [{
"id": "spring-shop",
"name": "Spring Shop",
"categories": [{
"id": "spring-shop-mens",
"name": "Spring Shop Men's",
"categories": []
}, {
"id": "spring-shop-womens",
"name": "Spring Shop Women's",
"categories": []
}]
}, {
"id": "the-festival-shop",
"name": "The Festival Shop",
"categories": [{
"id": "mens-festival-shop",
"name": "Mens Festival Shop",
"categories": []
}, {
"id": "womens-festival-shop",
"name": "Womens Festival Shop",
"categories": []
}]
}, {
"id": "buddha-collections",
"name": "The Icons Shop",
"categories": [{
"id": "buddha-collections-men",
"name": "Mens",
"categories": []
}, {
"id": "buddha-collections-women",
"name": "Womens",
"categories": []
}]
}, {
"id": "all-black",
"name": "All Black Everything",
"categories": []
}]
}]
}, {
"id": "denim",
"name": "DENIM",
"categories": [{
"id": "denim-view-all",
"name": "Shop All Denim",
"categories": [{
"id": "denim-view-all-mens",
"name": "Mens Denim",
"categories": []
}, {
"id": "denim-view-all-womens",
"name": "Womens Denim",
"categories": []
}, {
"id": "denim-view-all-kids",
"name": "Kids Denim",
"categories": []
}]
}, {
"id": "denim-collections",
"name": "Featured",
"categories": [{
"id": "denim-collections-signature-stitch",
"name": "Big T & Super T Stitch",
"categories": []
}, {
"id": "denim-collections-lighten-up",
"name": "Light Wash Denim",
"categories": []
}, {
"id": "dark-wash-denim",
"name": "Dark Wash Denim",
"categories": []
}]
}]
}]
}
This is what I have tried but being new to coding getting difficult to get list form this complex structure.
var rootCategories = (jsonData.categories);
for (var i=0; i < rootCategories.length; i++)
{
var firstChild = (jsonData.categories[i].categories);
for (var j=0; j < firstChild.length; j++)
{
if ((firstChild[j].categories[j].length != 0)) {
catId = firstChild[j].categories[j].id
console.log(catId);
}
}
}
Solution 1:[1]
Below is one possible way to achieve the target.
Code Snippet
// recursive method to get "id"s
const getIds = arr => (
arr.flatMap( // iterate using ".flatMap()" to avoid nesting
({id, categories}) => { // de-structure to directly access "id" & "categories"
if ( // if "categories" is not empty, recurse to next level
Array.isArray(categories) &&
categories.length > 0
) {
return getIds(categories);
} else { // if it is empty, simply return the id
return id;
}
}
)
);
const rawData = {
"categories": [{
"id": "featured",
"name": "NEW ARRIVALS",
"categories": [{
"id": "featured-new-arrivals",
"name": "New Arrivals",
"categories": [{
"id": "mens-new-arrivals",
"name": "Mens",
"categories": []
}, {
"id": "womens-new-arrivals",
"name": "Womens",
"categories": [{
"id": "mens-apparel-ricky",
"name": "Relaxed",
"categories": []
}, {
"id": "new-arrivals-kids",
"name": "Kids",
"categories": []
}, {
"id": "new-arrivals-accessories",
"name": "Accessories",
"categories": []
}]
}, {
"id": "collections",
"name": "Featured",
"categories": [{
"id": "spring-shop",
"name": "Spring Shop",
"categories": [{
"id": "spring-shop-mens",
"name": "Spring Shop Men's",
"categories": []
}, {
"id": "spring-shop-womens",
"name": "Spring Shop Women's",
"categories": []
}]
}, {
"id": "the-festival-shop",
"name": "The Festival Shop",
"categories": [{
"id": "mens-festival-shop",
"name": "Mens Festival Shop",
"categories": []
}, {
"id": "womens-festival-shop",
"name": "Womens Festival Shop",
"categories": []
}]
}, {
"id": "buddha-collections",
"name": "The Icons Shop",
"categories": [{
"id": "buddha-collections-men",
"name": "Mens",
"categories": []
}, {
"id": "buddha-collections-women",
"name": "Womens",
"categories": []
}]
}, {
"id": "all-black",
"name": "All Black Everything",
"categories": []
}]
}]
}, {
"id": "denim",
"name": "DENIM",
"categories": [{
"id": "denim-view-all",
"name": "Shop All Denim",
"categories": [{
"id": "denim-view-all-mens",
"name": "Mens Denim",
"categories": []
}, {
"id": "denim-view-all-womens",
"name": "Womens Denim",
"categories": []
}, {
"id": "denim-view-all-kids",
"name": "Kids Denim",
"categories": []
}]
}, {
"id": "denim-collections",
"name": "Featured",
"categories": [{
"id": "denim-collections-signature-stitch",
"name": "Big T & Super T Stitch",
"categories": []
}, {
"id": "denim-collections-lighten-up",
"name": "Light Wash Denim",
"categories": []
}, {
"id": "dark-wash-denim",
"name": "Dark Wash Denim",
"categories": []
}]
}]
}]
}]
};
console.log(getIds(rawData.categories));
.as-console-wrapper { max-height: 100% !important; top: 0 }
Explanation
Inline comments added in the snippet above.
Solution 2:[2]
If you're not afraid of reference loops (shouldn't technically happen in a serialized REST response) you can try recurring function as the simplest way to achieve this
function getIDs(node, isRoot = false) {
if (!node.categories.length) // if I understood your question correctly, you don't want parents to be printed out, otherwise just check for isRoot instead
return isRoot || console.log(node.id);
// with above you won't access non-existent id of the root collection
// because it will stop checking after first true statement
for (const category of categories)
getIDs(category);
}
getIDs(collection, true);
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | jsN00b |
| Solution 2 | waszqba |
