Enter an integer and find all palindromes lesser than or equal to the given number

Question

I do not understand why my code is not working, could anyone help me with this one? It is supposed to print a list of palindromes (numbers that are equal to themselves if read backwards) lesser than or equal to the input. When I try to execute it, it writes: /bin/sh: python: command not found.

w = input('Enter a number: ')
n = int(w)
g = []
for n in range(n, 0, -1):
    r = 0
    while n != 0:
        a = n % 10
        r = r * 10 + a
        n //= 10
    if n == r:
        g.append()
print(g)

Answer 1

You're almost there. Actually your if n == r: is always computing like if 0 == r:. Hence, in your for loop assign your n to a temp variable. Try this:

w = input('Enter a number: ')
n = int(w)
g = []
for n in range(n, 0, -1):
    temp = n
    r = 0
    while n != 0:
        a = n % 10
        r = r * 10 + a
        n //= 10
    
    if temp == r:
        g.append(temp)
print(g) 

Answer 2

You can use the following solution, which is simpler than using a while loop:

n = int(input("Enter a number:\n"))

g = []
for i in range(0, n+1):
    if str(i)==str(i)[::-1]:
        g.append(i)
print(g)

Answer 3

I don't think your code works anyway. Here is another way to find palindromes less than w:

w = input('Enter a number: ')
n = int(w)
palindromes = []
for i in range(n+1):
    if str(i) == str(i)[::-1]:
        palindromes.append(i)
print(palindromes)