Double the size of a list of random integers, then sort and print it

Question

Here, I have a list of random integers:

import random
list = [random.randint(0, 30) for x in range(6)]
pass

I want to double the size of this list, sort it, and print it. Here's what I've tried:

def list_doubled(list):
    doubled = []
    i = 0
    while i <= len(list):
        for item in list:
            doubled.append(list[i])
            doubled.append(list[i])
            i += 1
    print(doubled)

list_doubled(list)

This code is meant to only double the size of the list. When I run the program, I get "IndexError: list index out of range" with emphasis on lines 11 and 16.

Answer 1

Creating the list:

import random
numbers = [random.randint(0, 30) for x in range(6)]

Use extend to add the list to itself, in order to double it:

numbers.extend(numbers)   # or numbers += numbers

Or add as many random numbers as there are items in the list, if you need the additional numbers to also be random:

numbers.extend(random.randint(0, 30) for _ in range(len(numbers)))

use sort to sort it:

numbers.sort()

Use print to print it:

print(numbers)

Answer 2

Change your <= to < in your while loop line while i <= len(list):. You also might want to look at the comments, they have good advise on additional potential bugs you might encounter.