Display user choice from list [closed]

Question

Hi I'm writing a program currently I'm pretty new to python,

what I'm wanting is for the user to select from two options like so

1. Easy Mode
2. Hard Mode

Answer 1

You set Choice = int(...), so Choice is still 1 or 2, so when you print it it'll show up as 1 or 2. Instead, you could set a variable mode depending on which if statement is entered:

Choice = int(input("Select your difficulty: "))
mode = "Invalid choice" # Set a default value

if (Choice == 1):
  mode = "Easy Mode"
elif (Choice == 2):
  mode = "Hard Mode"

print ("Role: " , mode)

Of course, this doesn't account for the case when the user's input isn't one of these choices, but that's a different question: Asking the user for input until they give a valid response

Answer 2

Use a dictionary to associate the string the user enters with the one you want to display to them later:

difficulty = {
    "1": "Easy Mode",
    "2": "Hard Mode",
}

for c, desc in difficulty.items():
    print(f"{c}. {desc}")

choice = input("Select your difficulty: ")
while choice not in difficulty:
    choice = input(f"Choose one of: {', '.join(difficulty)}: ")

print(f"Role: {difficulty[choice]}")

1. Easy Mode
2. Hard Mode
Select your difficulty: asdf
Choose one of: 1, 2: 2
Role: Hard Mode