'Decode escaped characters in URL

I have a list containing URLs with escaped characters in them. Those characters have been set by urllib2.urlopen when it recovers the html page:

http://www.sample1webpage.com/index.php?title=%E9%A6%96%E9%A1%B5&action=edit
http://www.sample1webpage.com/index.php?title=%E9%A6%96%E9%A1%B5&action=history
http://www.sample1webpage.com/index.php?title=%E9%A6%96%E9%A1%B5&variant=zh

Is there a way to transform them back to their unescaped form in python?

P.S.: The URLs are encoded in utf-8

python escaping

Solution 1:^[1]

And if you are using Python3 you could use:

import urllib.parse
urllib.parse.unquote(url)

Solution 2:^[2]

or urllib.unquote_plus

>>> import urllib
>>> urllib.unquote('erythrocyte+membrane+protein+1%2C+PfEMP1+%28VAR%29')
'erythrocyte+membrane+protein+1,+PfEMP1+(VAR)'
>>> urllib.unquote_plus('erythrocyte+membrane+protein+1%2C+PfEMP1+%28VAR%29')
'erythrocyte membrane protein 1, PfEMP1 (VAR)'

Solution 3:^[3]

You can use urllib.unquote

Solution 4:^[4]

import re

def unquote(url):
  return re.compile('%([0-9a-fA-F]{2})',re.M).sub(lambda m: chr(int(m.group(1),16)), url)

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution	Source
Solution 1	Cadoiz
Solution 2	dli
Solution 3	Klaus Byskov Pedersen
Solution 4	mistercx

'Decode escaped characters in URL

Solution 1:[1]

Solution 2:[2]

Solution 3:[3]

Solution 4:[4]

Sources

Related Questions

Solution 1:^[1]

Solution 2:^[2]

Solution 3:^[3]

Solution 4:^[4]