Cubic Root in python without using the power operator

Question

I need your help in the following question

Print the greatest integer whose cube is smaller or equal to the input number without using the power operator ,you must use the print function and match the expected output :

• Print the following for input n=99: 4,not exact with difference 35

• Print the following for input n=2000: 12,not exact with difference 272

• Print the following for input n=1000: 10, exact!

  def cubic_root(n):
        if n<0:
           n=abs(n)
           cube_root = n**(1/3)*(-1)
        else:
            cube_root = n**(1/3)
            diff = round(n-(cube_root *cube_root *cube_root ))
            print (cube_root,"not exact with",diff)
    return cube_root
  
  print(round(cubic_root(99))) 
  print(round(cubic_root(2000))) 
  print(round(cubic_root(1000)))
  

My output:

4 not exact with 35
4
12 not exact with 272
12
9 not exact with 271
9

Answer 1

def cubic_root(n):
    n=abs(n)
    result=1
    x=2
    if n==0:
        print('0, exact!')
    elif n==1:
        print('1, exact!')
    else:
        while result<n:
            result=x*x*x
            if result>=n:
                break
            x=x+1
        if result!=n:
            x=x-1
        diff=(x*x*x)-n
        if diff==0:
            print('{0}, exact!'.format(str(x)))
        else:
            diff=abs(diff)
            print('{0}, not exact with difference {1}'.format(str(x), str(diff)))

Answer 2

def cubic_root(n):

n=abs(n)
result=1
x=2
if n==0:
    print('0, exact!')
elif n==1:
    print('1, exact!')
else:
    while result<n:
        result=x*x*x
        if result>=n:
            break
        x=x+1
    if result!=n:
        x=x-1
    diff=(x*x*x)-n
    if diff==0:
        print('{0}, exact!'.format(str(x)))
    else:
        diff=abs(diff)
        print('{0}, not exact with difference {1}'.format(str(x), str(diff)))

n = int(input("enter the value: ")) cubic_root(n)

##this worked for me