Converting List Comprehensions to For Loops in Python, if/else

Question

I have just started learning Python and would like to understand how to convert list comprehension to for loops together if if/elif/else statements.

Initial Question

Write a function, splitter that takes in an IC string, and outputs a tuple of the digits only. For example, if we do: a,b,c,d,e,f,g = splitter('S1234567D') a will store 1. b will store 2. ... g will store 7.

List Comprehension

• Suggested Answer

  def splitter(IC):

   a,b,c,d,e,f,g = [i for i in IC if i.isnumeric()]
  
   return a,b,c,d,e,f,g
  

• Testing the definition

  a,b,c,d,e,f,g = splitter('S1234567Z')

  print(a,b,c,d,e,f,g)

#Output 1 2 3 4 5 6 7

Main Question

If there a way to convert the above list comprehension to for loop using if/elif/else?

I have tried some variations, but am unable to run the cell as a,b,c,d,e,f,g expects 7 arguments and assigning a,b,c,d,e,f,g with an empty list and using append does not seem to work.

def splitter(IC):
    for i in IC[1:8]:
        if i.isnumeric():
            return a,b,c,d,e,f,g = splitter(IC)
        else:
            pass

Please help. Thank you!