Convert items in python list to paths

Question

I have a python list which I need to make changes to the items Here's my code till now

from pathlib import Path

BASE_DIR = Path.cwd()
MAIN_DIR = BASE_DIR / 'Files'

mylist = ['6', '112318', '112319']

# outputlist = ['C:\\Users\\Future\\Desktop\\Files\\112318.pdf', 'C:\\Users\\Future\\Desktop\\Files\\112319.pdf']

So the first item is to be skipped and the other items to be converted to be as paths for pdf files in Files directory.

@Daweo This is my attempt (can you please have a look and give me your review)

mylist = ['1', '112238', '112239', '112240', '112337', '165222', '112338']
files_list = [MAIN_DIR / f'{i}.pdf' for i in mylist[1:]]

final_list = []
final_list.append(mylist[0])

for file in files_list:
    if file.exists():
        final_list.append(file)       
    else:
        print(f'{file} ---> NOT Exists')  

print('=' * 50)
print(final_list)

Answer 1

I would do it following way from pathlib import Path

MAIN_DIR = Path("C:\\Users\\Future\\Desktop\\Files")
mylist = ['6', '112318', '112319']
outputlist = [MAIN_DIR / f'{i}.pdf' for i in mylist[1:]]
print(outputlist)

Output

[WindowsPath('C:/Users/Future/Desktop/Files/112318.pdf'), WindowsPath('C:/Users/Future/Desktop/Files/112319.pdf')]

Note: for sake of example simplicity I elected to use fixed MAIN_DIR. Features used: list slicing (to skip 1st element), f-string (for string formating, requires python3.6 or newer), list comprehension.