Conditional statement inside a match case

Question

Is it possible to have a conditional statement as a case for a match statement in Python?

Working something like this:

test = 'Aston Martin'
makes = ['Aston Martin', 'Bentley']

match test:
    case if test in makes:
        print(True)
    case _:
        print(False)

I know that match/case is not looking for something with boolean value True, but it seems like this would be useful to have for scaling things.

I tried to do it as a function so you can return the exact match:

test = 'Aston Martin'
makes = ['Aston Martin', 'Bentley']

def return_bool(item, lists):
    if item in lists:
        return item
    else:
        return 'notmatching'

match test:
    case return_bool(test, makes):
        print(True)
    case _:
        print(False)

This also didn't work. I think that it is expecting a format output, like - str(x)

I'm sorry if my explanation/vocabulary isn't right, please correct me as I am learning as I'm going along.

Answer 1

As the comments point out, the code you provided does seem like a better fit for if/elif, however it can be accomplished because match supports so-called "guard clauses".

test = 'Aston Martin'
makes = ['Aston Martin', 'Bentley']

match test:
    case test if test in makes:
        print(True)
    case _:
        print(False)

This works even in cases where makes is not a fixed sequence. If makes is really just a stand-in for a fixed sequence, then you could also use

test = 'Aston Martin'

match test:
    case 'Aston Martin' | 'Bentley':
        print(True)
    case _:
        print(False)

Note that you cannot do this

test = 'Aston Martin'
makes = ['Aston Martin', 'Bentley']

match test:
    case makes:
        print(True)
    case _:
        print(False)

as this will simply always match the first case, overwriting makes with test.

Answer 2

Use instead: if elif
Read to learn about match: PEP