'Compare if BigDecimal is greater than zero

How can I compare if BigDecimal value is greater than zero?

javacomparebigdecimal


Solution 1:[1]

It's as simple as:

if (value.compareTo(BigDecimal.ZERO) > 0)

The documentation for compareTo actually specifies that it will return -1, 0 or 1, but the more general Comparable<T>.compareTo method only guarantees less than zero, zero, or greater than zero for the appropriate three cases - so I typically just stick to that comparison.

Solution 2:[2]

Possible better way:

if (value.signum() > 0)

signum returns -1, 0, or 1 as the value of this BigDecimal is negative, zero, or positive.

Solution 3:[3]

Use compareTo() function that's built into the class.

Solution 4:[4]

it is safer to use the method compareTo()

    BigDecimal a = new BigDecimal(10);
    BigDecimal b = BigDecimal.ZERO;

    System.out.println(" result ==> " + a.compareTo(b));

console print

    result ==> 1

compareTo() returns

  • 1 if a is greater than b
  • -1 if a is less than b
  • 0 if a is equal to b

now for your problem you can use

if (value.compareTo(BigDecimal.ZERO) > 0)

or

if (value.compareTo(new BigDecimal(0)) > 0)

I hope it helped you.

Solution 5:[5]

using ".intValue()" on BigDecimal object is not right when you want to check if its grater than zero. The only option left is ".compareTo()" method.

Solution 6:[6]

This works in Kotlin:

value > BigDecimal.ZERO

Sources

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Source: Stack Overflow

Solution Source
Solution 1 Jon Skeet
Solution 2 EvilTak
Solution 3 Mariusz Jamro
Solution 4 Ajay Takur
Solution 5 Satya M
Solution 6

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