'Checking if a list is inside another list (regardless of order) in Python

I'm trying to build a slot machine game where you get 10 coins for getting 3 cherries (in any order) and I have an if statement like this:

#slotresult has the format ['x','x','x','x']
threecherries= ["cherry","cherry","cherry"]
  if set(threecherries).issubset(slotresult):
    print("Nice! You have won 10 coins!")

The problem is that it says 'You have won 10 coins!' when only one or more cherries appears in the slotresult, but I want it to only say this when there are three cherries there in any order.

I've also tried alternatives but they won't match if the result is like: ['cherry','lemon','cherry','cherry] as the 'cherries' aren't all next to each other!

Could anyone help me with this?

python list

Solution 1:^[1]

You can use list.count.

if slotresult.count('cherry') == 3:
    print("Nice! You have won 10 coins!")

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution	Source
Solution 1	Unmitigated

'Checking if a list is inside another list (regardless of order) in Python

Solution 1:[1]

Sources

Related Questions

Solution 1:^[1]