I have defined the following expression: r:sqrt((y1-x1)^2+(y2-x2)^2); When I differentiate r with respect to y1, i.e. diff(r,y1); I get the answer as (y1-x1)/sq
filter-driver
archunit
spotless
mapi
std-bitset
workqueue
gomail
fs2
kvm
windows-app-sdk
cupertinotabbar
tilesets
python-black
flatbutton
type-families
casbin
django-baton
relate
xslt-1.0
amba
azure-devops-extensions
secp256k1
toolbar
sourcegenerators
nopcommerce-4.3
sequel
python-keyring
azure-static-website-routing
bootstrap-selectpicker
vue-tables-2