Is there any way to limit how many items I want to get from a JSON request? the code I use: import json import requests url = 'https://api.github.com/users' re
I had a script that would login to my UPS.com account to receive all incoming packages. The following code was working for a while but not anymore: import reque
I don't know how to solve this problem i'm trying a long time now but i'm stuck. I've tried different Libarys for GraphQL requests but nothing is working so tha
I'm working on a personal project and I'm trying to retrieve air quality data from the https://aqicn.org website using their API. I've used this code, which I'v
I am trying to scrape https://registry.verra.org/app/search/VCS/All%20Projects for a school project. I am trying to send a request to the "download excel" butto
You see, there is this website called edabit. All you need to know is that I want to scrape the website without using selenium. I want to learn how. What does s
i'm trying to crawl website with python requests GET and having problem with Object.setPrototypeOf i added userAgent in header but it still gives me under code
I am trying to use requests.get with the Spotify API and I can't figure out why I keep getting a 400 response. I am working in an .ipynb file in Jupyter Lab run
I'm using the Requests library with Python 2.7 and get the following error: Traceback (most recent call last): File "/home/user/Documents/workspaces/controlle
I'm on macOS Monterey 12.3 running Python 3.9.7 installed via brew. Given this minimal replication of my production code: import requests try: response = r
I am using FastAPI to serve some ML models and I have a Streamlit basic UI using Python Requests module. One of my service is getting an image through a POST re
I hope for your help. Because I have been struggling with this problem for a long time. A POST request comes from the frontend with one PDF file, after which I
I have the following endpoint in my FastAPI server: @app.post("/submit") async def submit(file1: List[UploadFile] = File(...), file2: List[UploadFile] = File(..
I'm unable to connect to the URL using requests module, but it works fine when browsed in a browser. Could it be some robots.txt issue Allowed/Disallowed issue
I am trying to collect Captcha images using the Python requests module and save them to file or load in memory for further processing, but nothing works as belo
I need to create records in an airtable base and have the following code in scrapy: url = "https://api.airtable.com/v0/appuhKmlhLIIEszLm/Table%201" payload = j
I can unzip a url zip file of csvs using the below code: import requests from zipfile import ZipFile from io import BytesIO import pandas as pd z = 'www.someur
I have this file, abc.py: def asb(): print("Hello, ") def xyz(): print("World!") In my main.py file, from abc import asb from abc import xyz I want
I want to bypass Cloudflare on a GET request I have tried using Cloudscraper which worked for me in the past but now seems decreped. I tried: import cloudscrape
To make a POST call to the API, I use the following script: r = requests.post( url, headers={ "Content-Type": "application/json" }, json