z = zipfile.ZipFile("zipfile.zip", "w") z.write(filename) It takes string as an argument that is actually path of that file to be add to the zip. But I want t
memory-pool
insets
ebnf
android-scrolling
passkit
okta
broadcast-channel
formik-material-ui
trace
pyodbc
br-automation-studio
math-functions
prometheus-operator
agiletoolkit
webpack-isomorphic-tools
web-search
placement
input-method
jett
typesafe-config
telegraf.js
compass-sass
kotlin-when
flatfilesource
ios11
kartik-v
fixed-length-array
fragment-backstack
pandas-ta
danfojs