def min_heapify(A,k, n): left = 2*k +1 right = 2*k +2 n=int(len(A)) if left < n and A[left] < A[k]: smallest = left else:
mozart
temenos-quantum
python-asyncio
webdriver-w3c-spec
gstring
mendeley
row-removal
pydruid
cloudsim
react-wrapper
treenode
weak-ptr
jooq-codegen-maven
webusb
for-in-loop
coreldraw
invoices
firepath
rust-byteorder
azure-sql-server-managed-instance
accelerator
google-admin-settings-api
admob-rewardedvideoad
jointjs
currentvaluesubject
hasattr
android-uiautomator
nearcore
varint
ask-cli