def min_heapify(A,k, n): left = 2*k +1 right = 2*k +2 n=int(len(A)) if left < n and A[left] < A[k]: smallest = left else:
qt-slot
python-gitlab
google-app-engine-golang
ebnf
code-signing
brep
nvl
zend-db-table
flutter-pay
invoice
cim
scala-spark
code39
modelr
tika-server
vuejs-routing
echosign
angular-cdk-overlay
ubuntu-15.10
social-gaming
github-copilot
starvation
certificate-transparency
sql-server-profiler
usefaketimers
line
image-manipulation
faq
fatal-error
rtx