def min_heapify(A,k, n): left = 2*k +1 right = 2*k +2 n=int(len(A)) if left < n and A[left] < A[k]: smallest = left else:
jedi-vim
shakapacker
flutter-method-channel
android-diffutils
react-native-redash
gatling-plugin
virtualfilesystem
lmdb
sqlgeography
inotifycollectionchanged
documentclient
opencv4nodejs
purify
csv-parser
dia
spring-cloud-stream-binder-kafka
payload
smart-pointers
traversal
imageicon
sap-commerce-cloud
blackberry-webworks
android-appwidget
data-generation
abstract
questdb
sqlbulkcopy
linkify
log4r
flyspell