def min_heapify(A,k, n): left = 2*k +1 right = 2*k +2 n=int(len(A)) if left < n and A[left] < A[k]: smallest = left else:
xaml-islands
miragejs
whmcs-invoice-template
primefaces-8.0
elisp-macro
namedpipeserverstream
featherlight.js
phabricator
jpeg2000
google-directory-api
django-import-export-celery
pgbouncer
centos7.6
culture
dmv
data-filtering
primes
qmk
n8n
timage
nsurl
xor-linkedlist
vision-api
enum-map
onclick
circleci-orb
a86
clingo
restful-authentication
ata