can't figure out this kind of type in C++ (array of struct?) [closed]

Question

If I have a struct like this

struct my_struct
{
    float a, b;
};

Is there a way to declare an object by doing so?

my_struct[10][10] my_struct_inst;

If this is allowed, could anyone teach me how to understand this? Or what's the concept of this code?

So many thanks in advance.

Answer 1

Your syntax is simply wrong. Array size goes after the variable name, not the type:

my_struct my_struct_inst[10][10];

Note that the type of my_struct_inst is still my_struct[10][10], that's just the syntax for variable definitions.

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With modern C++, I would consider using std::array instead, though that's not pretty either:

std::array< std:array<my_struct, 10>, 10> my_struct_inst;

This is basically same thing and equally efficient, but it also offers a bunch of nice methods, which may be useful.

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To make that easier, you can define it as a type:

using my_struct_10x10 = std::array< std:array<my_struct, 10>, 10>;
my_struct_10x10 my_struct_inst;