'Can I order my CSS columns horizontally instead of vertically? Not using float or positioning [duplicate]

Not Using position and float, if any others way please help me Here is Html Code

<div class="column-content">
  <div class="single-column" style="height: 220px"></div>
  <div class="single-column" style="height: 160px"></div>
  <div class="single-column" style="height: 250px"></div>
  <div class="single-column" style="height: 150px"></div>
  <div class="single-column" style="height: 180px"></div>
  <div class="single-column" style="height: 120px"></div>
  <div class="single-column" style="height: 140px"></div>
  <div class="single-column" style="height: 190px"></div>
</div>

Here is Css Code

.column-content{
  column-count: 3;
}
.single-column{
  background: purple;
  width: 100%;
  display: inline-block;
  margin-bottom: 20px;
}
htmlcssstringhaskelltuplesghcirun-length-encoding


Solution 1:[1]

To expand on my comment;
You need to use inline-flex with combinations of widths to achieve your desired result;

.column-content {
  width: 100%;
  min-width: 100%;
}

.single-column {
  width:33%;
  min-width:33%;
  display: inline-flex;
  height: 100px;
  min-height: 100px;
  background-color: hotpink;
}

This can be tested in my JSFiddle although your heights throw it off

Solution 2:[2]

You can pattern-match also by multiple elements at the beginning of a list (like a:b:xs):

module Main where

import Data.Char

main = print $ unformat "1T3e1s1t" -- [(1,'T'),(3,'e'),(1,'s'),(1,'t')]

unformat :: String -> [(Int, Char)]
unformat (i:c:xs) = (digitToInt i, c) : unformat xs
unformat _ = []

Data.Char.digitToInt converts '0' to 0 and 'f' to 15, for example.

Solution 3:[3]

Here my solution with foldl. In each step we remember prev chars as a Jsut c if it's the first item of tuple or Nothing if it's second item of tuple.

module Main where

import Data.Char

main :: IO ()
main = print $ unformat "1T3e1s1t"

unformat :: String -> [(Int, Char)]
unformat s = snd $ foldl opr (Nothing , []) s
  where
    opr (prev, acc) c = case prev of
      Just n -> (Nothing, acc ++ [(digitToInt n, c)])
      Nothing -> (Just c, acc)

The output will be:

[(1,'T'),(3,'e'),(1,'s'),(1,'t')]

Sources

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Source: Stack Overflow

Solution Source
Solution 1 Can O' Spam
Solution 2
Solution 3 S4eed3sm

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