'C++ Dynamic Arrays Creation
I am prompted with the question as follows
- Write a program that prints dynamic arrays.
- The program creates an int 1D dynamic array of 3 elements and a float 2D dynamic array of 3 ROWS and 3 COLS.
- Initialize both arrays with random values.
- Both arrays will be printed separately in two separate functions
- void print_2d_array(float**);
- void print_1d_array(int*);"
I have created a code that will not produce any output. I am guessing the issue is in the initialization of the arrays, but I cannot figure it out. How do I get it to display the randomly generated numbers?
#include <iostream>
#include <iomanip>
using namespace std;
void print_2d_array(float**);
void print_1d_array(int*);
int main() {
srand(time(NULL));
int* arr[3];
float** arr_two[3][3];
for (int i = 0; i < 3; i++)
*arr[i] = rand() % 100;
for (int j = 0; j < 3; j++)
for (int k = 0; k < 3; k++)
**arr_two[j][k] = rand() % 100;
print_1d_array(*arr);
print_2d_array(**arr_two);
}
void print_2d_array(float** arr_two) {
for (int i = 0; i < 3; i++) {
for (int j = 0; j < 3; j++)
cout << arr_two[i][j];
}
cout << endl;
}
void print_1d_array(int* arr) {
for (int i = 0; i < 3; i++)
cout << arr[i];
}
Solution 1:[1]
I want to post my code because this was a nightmare for me with a lot of testing
This would help with a 1Dimensional array for dynamic array assignment
I can't find all the stack overflow comments that helped me reach this conclusion of code so, this is how I give back. Hopefully this helps make sense of it.
I read a lot of stack questions saying this isn't possible and use a vector, if I find them I intend to post this there as well.
#include <iostream>
#include <array>
using namespace std;
// Reference // https://www.learncpp.com/cpp-tutorial/dynamically-allocating-arrays/ // https://www.youtube.com/watch?v=FHhcSncuHEI
int main()
{
int size;
int number = 0;
int count = 0;
cout << "enter size for array: ";
cin >> size;
int *array;
int *tempArray;
tempArray = new int[size];
array = new int[size];
// can also be declared
// int *array = new int[size];
while(number != -1)
{
cout << " enter values for array: ";
cin >> number;
if(number == -1)
{
break;
}
if(count == size)
{
delete [] tempArray;
size = size + 1;
tempArray = new int[size];
for(int i=0; i < count; i++)
{
tempArray[i] = array[i];
}
delete [] array;
array = new int[size]; // re-use array pointer
for(int i=0; i < count; i++)
{
array[i] = tempArray[i];
}
}
array[count] = number;
count++;
}
// if(number == -1)
// {
// for(int i=0; i < count; i++)
// {
// cout << &array[i];
// }
// }
cout << endl;
// proves the array is tracking in memory to the same places.
// if it goes out of bounds of memory, the cout will just
// print the memory address of the last memory address block
// of the dynamic array, the assignment out of bounds does not
// cause significant change.
// array[0] = 1;
// array[1] = 2;
// array[2] = 3;
// array[3] = 4;
// cout << &array[0];
// cout << &array[1];
// cout << &array[2];
// cout << &array[3];
// cout << sizeof(array)/sizeof(array[0]);
// cout << endl;
// cout << array[0];
// cout << array[1];
// cout << array[2];
// cout << array[3];
// cout << array[4];
// cout << array[5];
// cout << endl;
for(int i=0; i < size; i++)
{
cout << "array element " << i << ": " << array[i] << endl;
}
return 0;
}
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Robert Petersen |
