Batch: Iterate .csv file columns

Question

I have this .csv file:

col0,col1,col2,col3,col4
a,1,10,100,1000
b,2,11,101,1001
c,3,12,102,1002
d,4,13,103,1003
e,5,14,105,1004

I need to iterate each column in the .csv without knowing the number of columns. First column is skipped because is not needed. I have this code so far, but I need a solution for the case where I don't know the number of columns. I need the value of each column in a later step where I calculate something.

@echo off
setlocal enableDelayedExpansion
:: set workspace data
set INPUT_FILE_LOCATION=D:\Scripts\
set CSV_FILE_NAME=test.csv

pushd %INPUT_FILE_LOCATION%
::loop through the csv file
for /F "tokens=2,3,4,5 delims=," %%i in (%CSV_FILE_NAME%) do (
echo %%i,%%j,%%k,%%l
rem echo.%%~i^|END
)
endlocal 

To be more specific, I have a .csv file, with some columns and many many rows. Starting with the second column, I will need to make the difference of every two elements of every column to verify if there is at least one difference greater than 1.(The values on columns are going to be in ascending order, so as an example using the csv above, the code should do the following: starting on col1, verify if 2-1 > 1, then if 3-2 > 1, then if 4-3 > 1 then 5-4 > 1, then it should verify the same thing for the next column(col2) and so on, until we reach the last column. If I will find one difference greater than 1, I want to print a message that "a bigger difference was found on" the header of that column where the bigger difference was found; Somehow I want to localize in which column was found the unexpected difference by using the title of the column from the header; for example, in col3, we have a difference greater than 1 and I want to print "there's a difference greater than 1 in col3", where col3 is in the header). In time, I will need to add some more columns, so the file could have 30 or 40 columns with the same structure like the previous ones.