Basic problem with solving differential equation with ODEINT in python

Question

I have implemented solver like below:

def kaiABC(X, t, 
           kut0, kutA, kdt0, kdtA, ktu0, ktuA, ktd0, ktdA,
           kus0, kusA, kds0, kdsA, ksu0, ksuA, ksd0, ksdA, 
           K): # 19 arguments

    Atot = 1.3
    Ctot = 3.4

    (S, T, D) = X 

    U = Ctot - S - T - D
    A = max(0, Atot, 2*S)

    kut = kut0*K/(K+A) + kutA*A/(K+A)
    kdt = kdt0*K/(K+A) + kdtA*A/(K+A)
    ktu = ktu0*K/(K+A) + ktuA*A/(K+A)
    ktd = ktd0*K/(K+A) + ktdA*A/(K+A)
    kus = kus0*K/(K+A) + kusA*A/(K+A)
    kds = kds0*K/(K+A) + kdsA*A/(K+A)
    ksu = ksu0*K/(K+A) + ksuA*A/(K+A)
    ksd = ksd0*K/(K+A) + ksdA*A/(K+A)

    dSdt = kus*U + kdt*D - ktu*T - ktd*T
    dTdt = ktd*T + ksd*T - kdt*D - kds*D
    dDdt = kus*U + kds*D - ksu*S - ksd*S

    return [dSdt, dTdt, dDdt]

and when I have to solve like this:

t = np.linspace(0, 20)

# The initial conditions
S = 0.34
T = 0.68
D = 1.36

X = (S, T, D)

kut0 = 0
kutA = 0.48
kdt0 = 0
kdtA = 0.17
ktu0 = 0.21
ktuA = 0.29
ktd0 = 0
ktdA = 0.21
kus0 = 0
kusA = 0.05
kds0 = 0.31
kdsA = 0
ksu0 = 0.11
ksuA = 0
ksd0 = 0
ksdA = 0.51
K = 0.43

p = (kut0, kutA, kdt0, kdtA, ktu0, ktuA, ktd0, ktdA,
     kus0, kusA, kds0, kdsA, ksu0, ksuA, ksd0, ksdA, 
     K) # 17 arguments

ret = odeint(kaiABC, X, t, args=p)
kut, kdt, ktu, ktd, kus, kds, ksu, ksd = ret.T

I have an error:

ValueError: not enough values to unpack (expected 8, got 3)

In my opinion all argument are in their places. Anyone where is the problem and how to sole it?

Any advices?

Problem related to number of arguments, it is either too low or to much.

Please help, the problem has to be basic.