'Append every n bytes into a byte array
b"\x00\x01\x02\x03\x04\x05\x06\x07\x08\x09\x0A"
How do I append bytes (e.g. b"\xFF") every n bytes (e.g. 2), so it becomes:
b"\x00\x01\xFF\x02\x03\xFF\x04\x05\xFF\x06\x07\xFF\x08\x09\xFF\x0A"
Solution 1:[1]
Iterate on it with a chunk_size of 2, to cut in several pieces of len 2, then join it
value = b"\x00\x01\x02\x03\x04\x05\x06\x07\x08\x09\x0A"
result = b'\xFF'.join(value[i:i + 2] for i in range(0, len(value), 2))
print(result) # b'\x00\x01\xff\x02\x03\xff\x04\x05\xff\x06\x07\xff\x08\t\xff\n'
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | azro |