'Angular 6 ng lint combineLatest is deprecated
I recently updated from Angular 5 to Angular 6.
I'm getting this warning combineLatest is deprecated: resultSelector no longer supported, pipe to map instead. Rxjs is version 6.1.0, tslint is 5.10.0, Angular CLI is 6.0.0 and Typescript 2.7.2. I'm using it like this:
const a$ = combineLatest(
this.aStore.select(b.getAuth),
this.cStore.select(b.getUrl),
(auth, url) => ({auth, url}),
);
I've tried it also like this:
empty().pipe(
combineLatest(...),
...
)
But this gives me: combineLatest is deprecated: Deprecated in favor of static combineLatest and empty is also deprecated in favor of its static version.
Solution 1:[1]
combineLatest is deprecated: resultSelector no longer supported, pipe to map instead
The above warning is recommending to remove the resultSelector the last function you provided in combineLatest observable and provide it as part of map operator as follows
const a$ = combineLatest(
this.aStore.select(b.getAuth),
this.cStore.select(b.getUrl)
);
const result$ = a$.pipe(
map(results => ({auth: results[0], url: results[1]}))
)
UPDATE:
If you see combineLatest is deprecated: Pass arguments in a single array instead then just add []:
const a$ = combineLatest([
this.aStore.select(b.getAuth),
this.cStore.select(b.getUrl)
]);
const result$ = a$.pipe(
map(results => ({auth: results[0], url: results[1]}))
)
Solution 2:[2]
Unfortunately you might also get that tslint error if you import combineLatest from operators:
import { combineLatest } from 'rxjs/operators';
combineLatest(...array);
instead of,
import { combineLatest } from 'rxjs';
combineLatest(...array);
Solution 3:[3]
Unlike the deprecated versions, combineLatest accepts an Array of Observable and returns an array containing the latest values from each. Every stream has to yield in order for combineLatest to yield.
fruitType$ = combineLatest([this.entity$, this.datasetStateService.get$('Fruits')])
.pipe(map(data => {
const entity = data[0];
const dataset = data[1];
return {
isApple: (dataset.find(ds => ds.label === 'Apple') as DataItem).id === entity.fruitId,
isOrange: (dataset.find(ds => ds.label === 'Orange') as DataItem).id === entity.fruitId
}
}));
Solution 4:[4]
For trailing comma error, remove the comma after (auth, url) => ({auth, url})
const a$ = combineLatest(
this.aStore.select(b.getAuth),
this.cStore.select(b.getUrl),
(auth, url) => ({auth, url}), // Remove this comma.
);
For missing import error, Make sure you have imports for all the external var's or classes you are using in the file.
Example, in this case, if you havent imported combineLatest, then import it
import { combineLatest } from 'rxjs'; // For RxJS 6.x
import { combineLatest } from 'rxjs/operators'; // For RxJS 5.x
Solution 5:[5]
In my case it's because I explicitly set generic argument, so an incorrect combineLatest overload was selected. To get rid of the warning I've changed
combineLatest<void>([
firstObservable$,
secondObservable$
]);
to
combineLatest([
firstObservable$,
secondObservable$
]).pipe(
mapTo(undefined)
);
Solution 6:[6]
I would solve that this way:
auth$ = this.aStore.select(b.getAuth);
url$ = this.cStore.select(b.getUrl);
combinedResult$ = combineLatest([this.auth$, this.url$]).pipe(
map(([auth, url]) => ({auth, url}))
)
Solution 7:[7]
This error can also be caused by passing in an array of Subscription items, instead of actual observables, lol. (I got really sloppy on this one.)
WRONG!
const foo = Foo$.subscribe(f => {
// do something with f here
})
const bar = Bar$.subscribe(b => {
// do something with b here
})
combineLatest([foo, bar]).subscribe(([f, b]) => {
// do something after both foo$ and bar$ have emitted something
})
CORRECT!
const foo$ = Foo$.pipe(
tap(f => {
// do something with f here
})
)
const bar$ = Bar$.pipe(
tap(b => {
// do something with b here
})
)
combineLatest([foo$, bar$]).subscribe(([f, b]) => {
// do something after both Foo$ and Bar$ have emitted something
})
Solution 8:[8]
i used depricated combineLatest to combine those two observables this.route.paramMap + this.route.queryParamMap:
combineLatest(this.route.paramMap, this.route.queryParamMap)
.subscribe(combined => {
const idFollower = combined[0].get('id');
const page = combined[1].get('page');
})
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | |
| Solution 2 | |
| Solution 3 | |
| Solution 4 | Basavaraj Bhusani |
| Solution 5 | Valeriy Katkov |
| Solution 6 | Prezes |
| Solution 7 | Trevor |
| Solution 8 | Mo. |
