Alternatives to (A && B) || (!A && !B) conditions . Flag switching behaviour

Question

I'm refactoring some code where there are a bunch of statements like this:

const color = isDark
  ? isOdd
    ? 'white'
    : 'black'
  : isOdd
    ? 'black'
    : 'white'

Note that we could swap isDark with isOdd and get the exact same results.

The code essentially has two possible outcomes depending on a condition –being odd in the example–, and a flag that switches de behaviour –isDark in the example–.

I don't find that code very readable, so I was looking for alternatives. The ones I found are:

const first = (isDark && isOdd) || (!isDark && !isOdd) ? 'white' : 'black'

const second = isDark === isOdd ? 'white' : 'black'

The first statement is probably more explicit about what's going on. The second statement is a shorter version, but probably the least readable.

What are other alternatives in this scenario?