Accessing items in odict_items [closed]

Question

I have odict_items that is looking like below. Here is the printed output of Ordereddict items that I have

odict_items([('S.No', '1'), ('Name', 'Ventura'), ('Location', 'Ph'), ('OL', 'ML'), ('Tech', 'IT'), ('Value', 223)])
odict_items([('S.No', '4'), ('Name', 'Ventura'), ('Location', 'Ph'), ('OL', 'ML'), ('Tech', 'IT'), ('Value', 223)])
odict_items([('S.No', '15'), ('Name', 'Ventura'), ('Location', 'Ph'), ('OL', 'ML'), ('Tech', 'IT'), ('Value', 223)])

How can I access the S.No key from each item and group the values 1, 4, 15?

Answer 1

I have to assume here that you have something similar to the following situation at some point:

ods = [ OrderedDict(<your data>), OrderedDict(<your data>), OrderedDict(<your data>) ]
for d in ods:
    print(d.items())

If you still have the dictionaries these came from, you can and should access the value using d['S.No'].

If for some reason you do not still have the OrderedDicts themselves, you can make a function to get the value:

def get_sno(od_items):
    for item in od_items:
        if item[0] == 'S.No':
            return item[1]
    return None

Used as such:

snos = []
for d in ods:
    snos.append(get_sno(d.item()) # preferably snos.append(d['S.No']) instead