access List within List and check index for item changed in 2nd list

Question

I am trying to get data from list within list

data1 = [['Once per day', '50 times per day', 'Once per week', 'Twice per day'], ['Serverless', 'Infrastructure as a Service', 'Hybrid Compute', 'Virtual Machine Scale Set']]


data2 = [['Twice per day', '50 times per day', 'Once per day', 'Once per week'], ['Virtual Machine Scale Set', 'Infrastructure as a Service', 'Hybrid Compute', 'Serverless']]

I am trying to check in which index the first item from data1 is in data2 for example

Sample Output
3
4

as "Once per day" first item from data1 is changed to index 3 in data2 and adding 1 to index

Answer 1

I would iterate over the length of data1[0] or data2[0] and compare the value of each element. If they are different then you have found your index.

data1 = [['Once per day', '50 times per day', 'Once per week', 'Twice per day'], ['Serverless', 'Infrastructure as a Service', 'Hybrid Compute', 'Virtual Machine Scale Set']]


data2 = [['Twice per day', '50 times per day', 'Once per day', 'Once per week'], ['Virtual Machine Scale Set', 'Infrastructure as a Service', 'Hybrid Compute', 'Serverless']]

d1 = data1[0]
d2 = data2[0]

for i in range(len(d1)):
    if d1[i] != d2[i] 
        print(0,i)
        break

Answer 2

Accessing a list within a list is done via successive square brackets like print data1[0][0] would return Once per day. The rest of the process would be done via for loops!

Answer 3

A short way to do it :

L = [(data2[i].index(data1[i][0] ) +1) for i in range(len(data1)) ]
print(L)

output :

[3, 4]