'4.5.1 Detect Number Range Zybook
Write an expression that prints "Eligible" if user_age is between 18 and 25 inclusive. Ex: 17 prints "Ineligible", 18 prints "Eligible".
user_age = int(input())
if ''' Your solution goes here ''':
print('Eligible')
else:
print('Ineligible')
I keep putting (user_age <= 25) what am I doing wrong?
Solution 1:[1]
Here is the correct code for CHALLENGE ACTIVITY 5.2.1: Detect number range.
Write an expression that prints "Eligible" if user_age is between 18 and 25 inclusive.
Ex: 17 prints "Ineligible", 18 prints "Eligible".
user_age = int(input())
if user_age >= 18 and user_age <= 25 :
print('Eligible')
else:
print('Ineligible')
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | aaossa |
