'XPath for text after <br/>

Looking to get the XPath of $2.00 with this block: 

<td class="undefined" colspan="6">
   <table class="history-bill-payments" cellspacing="0" cellpadding="0" border="0" align="center" width="99%">
<thead>
<tbody>
   <tr>
      <td valign="top">04/19/2016</td>
      <td valign="top" style="text-align:right; height:">
         $3.00
         <br/>
         $2.00
      </td>

I have tried these but to no avail

$I->CanSeeElement("//table[contains(tbody/tr[2]/td/table/tbody/tr/td[2]/following-sibling::br)]"); 
$I->CanSeeElement("//table[contains(tbody/tr[2]/td/table/tbody/tr/td[2]/preceding-sibling::br/text(),'$2.00')]"); 
$I->CanSeeElement("//table[contains(tbody/tr[2]/td/table/tbody/tr/td[2]/following-sibling::br/text(),'$2.00')]");

Using firepath in Firefox I get this XPath

html/body/div[4]/div[2]/div/div/div/div/table/tbody/tr[2]/td/table/tbody/tr/td[2]

I was able to get the xpath of $3.00

$I->CanSeeElement("//table[contains(tbody/tr[2]/td/table/tbody/tr/td[2]/text(),'$3.00')]");
htmlxmlxpathcodeception


Solution 1:[1]

td with certain contents

From your trials, it seems you're fine with keying off of $2.00 literally, so you could use this XPath 2.0 expression to get the td that ends with $2.00:

//td[ends-with(normalize-space(), '$2.00')]

Note that browsers don't generally support XPath 2.0, so use this XPath 1.0 expression if running within a browser and you're ok with $2.00 appearing anywhere within the td:

//td[contains(.,'$2.00')]

Text following a br

If you don't want to literally specify the $2.00, you'll have to state some other invariant constraint. For example, this XPath will return the string that follows the br contained within a td that starts with $3.00:

normalize-space(//td[starts-with(normalize-space(),'$3.00')]/br/following::text())

See also

Solution 2:[2]

If you need, just add table id or any other specific locator.

xpath=//table//tr/td[2]/text()[2]

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source
Solution 1
Solution 2 Tomas Chudjak

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