'Xdebug xdebug.mode = debug not working for me

I have installed Xdebug on a Ubuntu 20.04 system. I followed this documentation , which I found to be quite well written, and got everything installed per the specs. (I used apt rather than yum, and placed the .so file into /usr/lib/php/20190902 folder rather than the document's example.)

In that document, there is a reference to adding to the php.ini file (I added to /etc/php/7.4/apache2/php.ini and /etc/php/7.4/cli/php.ini files). Since the article doesn't specifically mention "sections" of the .ini file, I put them within the [PHP] section. (This is consistent with the remark about putting right before the Quick Reference bit.) I restarted Apache2 and the phpinfo() output now includes Xdebug, which it did not include before. All well and good.

The trouble I'm having is that although I set xdebug.mode = debug in the php.ini files, the phpinfo() output tells me that xdebug.mode is set to develop. Consequently, Step debugger shows as Disabled in my configuration. I cannot see why.

These are the lines I've added to each of those php.ini files:

zend_extension="/usr/lib/php/20190902/xdebug.so
xdebug.mode = debug
xdebug.discover_client_host = 1
xdebug.start_with_request = yes

And here are the key excerpts from the phpinfo() output:

Xdebug settings 1

Xdebug settings 2

On a whim, I tried placing all of those settings also within a new section of php.ini which I called [xdebug]. When that didn't work, I tried [Xdebug]. I restarted Apache2 after each attempt, but the symptom never changed.

What might I be missing?

phpxdebugphp-7.4xdebug-3


Solution 1:[1]

zend_extension="/usr/lib/php/20190902/xdebug.so (that has an extra ").

In any case, it is very likely that there is either another xdebug.mode line somewhere, or a different INI file is being used. Try to see what the output of xdebug_info() tells you — it also mentions which INI files have been read.

Solution 2:[2]

I'm here to help anyone with Xdebug on a Windows system and PHP 7.4 installed. Can try to set the php.ini as shown below. Can see my xdebug extension is called php_xdebug.dll inside this folder C:\xampp\php\ext\

xdebug.remote_autostart = 0
xdebug.mode = debug
xdebug.start_with_request = yes
zend_extension = C:\xampp\php\ext\php_xdebug.dll
xdebug.stopOnEntry = true
xdebug.profiler_enable = off
xdebug.profiler_enable_trigger = Off
xdebug.profiler_output_name = cachegrind.out.%t.%p
xdebug.output_dir ="c:\xampp\tmp"
xdebug.show_local_vars=0
xdebug.remote_handler = "dbgp"
xdebug.client_host = "127.0.0.1"
xdebug.log = "C:\xampp\tmp\xdebug.txt"
xdebug.client_port = 9000
xdebug.remote_cookie_expire_time = 36000

*Extras for the visual studio code user. Make sure the port inside the configuration is the same as the one that you set.

{
    // Use IntelliSense to learn about possible attributes.
    // Hover to view descriptions of existing attributes.
    // For more information, visit: https://go.microsoft.com/fwlink/?linkid=830387
    "version": "0.2.0",
    "configurations": [
        {
            "name": "Listen for Xdebug",
            "type": "php",
            "request": "launch",
            "port": 9000
        },
        {
            "name": "Launch currently open script",
            "type": "php",
            "request": "launch",
            "program": "${file}",
            "cwd": "${fileDirname}",
            "port": 0,
            "runtimeArgs": [
                "-dxdebug.start_with_request=yes"
            ],
            "env": {
                "XDEBUG_MODE": "debug,develop",
                "XDEBUG_CONFIG": "client_port=${port}"
            }
        },
        {
            "name": "Launch Built-in web server",
            "type": "php",
            "request": "launch",
            "runtimeArgs": [
                "-dxdebug.mode=debug",
                "-dxdebug.start_with_request=yes",
                "-S",
                "localhost:0"
            ],
            "program": "",
            "cwd": "${workspaceRoot}",
            "port": 9000,
            "serverReadyAction": {
                "pattern": "Development Server \\(http://localhost:([0-9]+)\\) started",
                "uriFormat": "http://localhost:%s",
                "action": "openExternally"
            }
        }
    ]
}

Sources

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Source: Stack Overflow

Solution Source
Solution 1 Derick
Solution 2 Ras

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