'Why the out put of below code is Thread[main,5,main]

public class test1 {
    public static void main(String[] args) {
        // TODO Auto-generated method stub
        Thread t = Thread.currentThread();
        System.out.println(t);
    }
}

Why the output of above code is - Thread[main,5,main] ? Please Explain

javamultithreadingmainvoid


Solution 1:[1]

Because thread.toString() returns a string representation of this thread, including the thread's name, priority, and thread group.

Solution 2:[2]

Returns a string representation of this thread, including the thread's name, priority, and thread group.

Source: https://docs.oracle.com/javase/7/docs/api/java/lang/Thread.html#toString()

Solution 3:[3]

Because of:

/**
 * Returns a string representation of this thread, including the
 * thread's name, priority, and thread group.
 *
 * @return  a string representation of this thread.
 */
public String toString() {
    ThreadGroup group = getThreadGroup();
    if (group != null) {
        return "Thread[" + getName() + "," + getPriority() + "," +
                       group.getName() + "]";
    } else {
        return "Thread[" + getName() + "," + getPriority() + "," +
                        "" + "]";
    }
}

Solution 4:[4]

https://docs.oracle.com/javase/7/docs/api/java/lang/Thread.html#toString()

public String toString()
Returns a string representation of this thread, including the thread's name, priority, and thread group.

Here is how we can find the definition:

    @FastNative
    public static native Thread currentThread();

There is no need to check the native method, just notice that the return type is Thread, so check the Thread.toString definition in Thread.

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Android SDK has the source code.

    /**
     * Returns a string representation of this thread, including the
     * thread's name, priority, and thread group.
     *
     * @return  a string representation of this thread.
     */
    public String toString() {
        ThreadGroup group = getThreadGroup();
        if (group != null) {
            return "Thread[" + getName() + "," + getPriority() + "," +
                           group.getName() + "]";
        } else {
            return "Thread[" + getName() + "," + getPriority() + "," +
                            "" + "]";
        }
    }

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source
Solution 1 Shree Krishna
Solution 2 AdrianS
Solution 3 gmaslowski
Solution 4 Francis Bacon

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