Why Task.Start() does not wait on Task.Delay()? [duplicate]

Question

I don't understand why the following code executes .ContinueWith() before Task.Delay() has ended its execution.

static void Main(string[] args)
{
    Task t = new Task(async () =>
    {
        Console.WriteLine("1 delaying");
        await Task.Delay(2000);
        Console.WriteLine("2 delayed");
    });

    t.Start();
    t.ContinueWith(_ => Console.WriteLine("3 continue"));

    Console.ReadKey();
}

Output is:

1 delaying 
3 continue 
2 delayed

But I was expecting that "3 continue" should be executed as last.

With Task.Run() it works as expected:

Task.Run(async () =>
{
    Console.WriteLine("1 delaying");
    await Task.Delay(2000);
    Console.WriteLine("2 delayed");
})
.ContinueWith(_ => Console.WriteLine("3 continue"));

Console.ReadKey();

Results in:

1 delaying
2 delayed
3 continue

In my case, I have to create a Task and start it later. How can I achieve that a created Task awaits Task.Delay() without executing the next Task (.ContinueWith()) first?