Why is the c++ program not outputting the modified pointer-to-pointer variable results in the caller function? [duplicate]

Question

I am developing a tic-tac-toe board game in c++ for learning purposes, and I am passing a char** to a function that assigns the given parameter an array of pointers which stores a players name.

Upon variable assignment, I am able to print the results of the initialized variable in the function call to void initPlayerNames(char** playerNames) but when I return to the caller function the program does not print the results.

My understanding is that a pointer variable stores the address of another data structure, therefore I expect to print the results of the pointer variable after it has been modified in the function call.

Please help me understand where I am making a mistake

void initPlayerNames(char** playerNames) {
   const int playerNameLength = 100; 

   cout << "Player one, enter your name: "; 
   char p1[playerNameLength];
   cin.getline(p1, playerNameLength);

   cout << "Player two, enter your name: "; 
   char p2[playerNameLength]; 
   cin.getline(p2, playerNameLength);

   char* names[2] = {p1, p2}; 
   playerNames = names; 

   cout << "Player 1 = " << playerNames[0] << endl; 
   cout << "Player 2 = " << playerNames[1] << endl; 

}; 

void game() {

   char** playerNames = nullptr; 
   cout << "Welcome! \n";  

   initPlayerNames(playerNames); 
   cout << "Player 1 = " << playerNames[0] << endl; 
   cout << "Player 2 = " << playerNames[1] << endl; 

};

Output

Player one, enter your name: Kevin Patel

Player two, enter your name: Steve Jobs

Player 1 = Kevin Patel

Player 2 = Steve Jobs