'Why is std::iterator deprecated?
Template class std::iterator is set to be deprecated in C++17. Why so? It has been a handy way to make sure std::iterator_traits works, especially if you can make use of the default template arguments. Is there some other way of doing it in C++17?
Solution 1:[1]
As Barry states, the working group has decided that explicitly declaring the types in the class is more readable and leads to less surprises than inheriting from std::iterator.
It's not too hard, though, to convert to the explicit types (below example taken from www.fluentcpp.com here). Given a class that was declared like so:
class MyIterator
: public std::iterator<std::forward_iterator_tag, int, int, int*, int&>
{
...
The class without std::iterator becomes:
class MyIterator
{
public:
using iterator_category = std::forward_iterator_tag;
using value_type = int;
using difference_type = int;
using pointer = int*;
using reference = int&;
// ...
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | firebush |
