'Why can't I use map on the result of a querySelectorAll?
I recently needed to extract the value of several nodes from an HTML document. I got the nodes using querySelectorAll, which returns a list of the nodes that meet the criteria. I had used arr.map before, so I tried to do it like this (which did not work):
var elems = document.querySelectorAll('select option:checked');
values = elems.map(function(obj) {return obj.value});
When I read the documentation in MDN, I saw that I had to use something like this instead:
var elems = document.querySelectorAll('select option:checked');
var values = Array.prototype.map.call(elems, function(obj) {
return obj.value;
});
My question is, if what I get from querySelectorAll is an array, why can't I use the first expression, like I would for any other array?
Solution 1:[1]
My question is, if what I get from querySelectorAll is an array, why can't I use the first expression, like I would for any other array?
querySelectorAll
does not return an array, it returns a NodeList
.
From MDN (emphasis mine):
Returns a list of the elements within the document (using depth-first pre-order traversal of the document's nodes) that match the specified group of selectors. The object returned is a NodeList.
NodeList
does not have Array.prototype
in its prototype chain, so it doesn't have the array methods.
Solution 2:[2]
As others pointed out, a node list (querySelectorAll) is not the same as an Array. With ES6 you can do this as a one liner with the spread operator (which converts to an array):
const checkedOptions = [...document.querySelectorAll('select option:checked')].map(option => option.value);
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
Solution | Source |
---|---|
Solution 1 | Felix Kling |
Solution 2 | Charles Owen |