Where did I make a mistake in this linux bash code?

Question

This code always returns the TRUE answer but the value of $myvar is "null"

if [ $myvar = "true" ]
then
cat << EOF > file1
blabla
EOF
echo $myvar
else
cat << EOF > file1
blublu
EOF
echo $myvar
fi

Where did I make a mistake ? Many Thanks Olive

Answer 1

There are multiple obvious errors in the command.

About your if statement:

First of all, square brackets [] are an alternative version of the test command. You want to use no brackets or parentheses ().

When writing oneliner you need to end each part of the command with a semicolon ; or that your shell knows at which point you start a new command.

Also in nearly all cases you want to quote your variables.

This leaves you with the following:

if "$myvar" = "true"; then echo "is true"; echo "some other command";  else echo "is not true"; echo "another command; fi

I cannot say much about the rest of the command, as it is unclear what you are trying to do with all of these EOFs.