'Where are the parentheses in an explicit convertion written? [closed]

Why is an explicit conversion written like

int operand = 1;
byte result = (byte)operand;

instead of

int operand = 1;
byte result = byte(operand);

?

Is byte in the former treated as an operator?

Is byte in the latter treated as a method?

Thanks.

c++sharp


Solution 1:[1]

Yes, it is indeed an (unary) operator. You can even create your own ones using following syntax:

public static explicit operator MyType(OtherType t)
{
    // return instance of MyType
}

Solution 2:[2]

It's written inside of the parameters. It comes from C/C++. There's no method called byte. It's an explicit cast defined by .NET. byte is a C# keyword/alias for System.Byte.

Sources

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Source: Stack Overflow

Solution Source
Solution 1 adjan
Solution 2 halfer

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