'Using AWK to skip first line and pattern match for the rest

In the following text, I would like to skip the first line and put $ in front of lines starting with Part1. I have included my script, but it not working. Can you please help?

Input
------
Intro
Part1 Yellow
Part2 Red
Part3 Green
Part1 Yellow

Desired output:
--------------
$Part1 Yellow
Part2 Red
Part3 Green
$Part1 Yellow

Code:
awk 'NR>1 {$0~/Part1/($0="$ "$0)}1' myfile

Error:
awk: Syntax error  Context is:
>>>     NR>1 {$0~/Part1/(       <<<
shellawk


Solution 1:[1]

With your shown samples please try following awk. Simple explanation would be, its skipping 1st line(FNR>1) condition AND its checking if a line starts with Part1 then its adding $ in front of current line's value. Then mentioning 1 will print the edited/non-edited line.

awk 'FNR>1 && /^Part1/{$0="$"$0} 1' Input_file

Solution 2:[2]

If you want to skip the first line and not to print it, I'd make this change in your code:

awk 'NR>1 {if ($0 ~ /^Part1/) $0="$"$0;print}' file

or more concise:

awk 'NR > 1 {if (/^Part1/) $0="$"$0;print}' file
$Part1 Yellow
Part2 Red
Part3 Green
$Part1 Yellow

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source
Solution 1
Solution 2 Carlos Pascual

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