'Using a condition related to a part of word in r
I have a dataframe like this:
1 2
aquiles_alcatra_Mat_15 picanha
aquiles_alcatra_Mat_15 picanha
alcatra_Mat_15 picanha
alcatra_Mat_20 picanha
alcatra_Mat_25 picanha
picanha_Mat_20 picanha
picanha_Mat_25 picanha
and I would like to do this:
1 2
aquiles_alcatra_Mat_15 alcatra
aquiles_alcatra_Mat_15 alcatra
alcatra_Mat_15 alcatra
alcatra_Mat_20 alcatra
alcatra_Mat_25 alcatra
picanha_Mat_20 picanha
picanha_Mat_25 picanha
If I have alcatra as a part of the word on column 1 I will just want alcatra on column 2.
I know I can use this:
file$2[ file$1 == 'aquiles_alcatra_Mat_15'] <- 'alcatra'
but I have several situations almost 300. And I tried something like this:
file$2[ file$1 == '.*alcatra*'] <- 'alcatra'
But did'nt work.
Solution 1:[1]
A possible solution, based on dplyr and stringr::str_detect:
library(tidyverse)
df %>%
mutate(V2 = if_else(str_detect(V1, "alcatra"), "alcatra", V2))
#> V1 V2
#> 1 aquiles_alcatra_Mat_15 alcatra
#> 2 aquiles_alcatra_Mat_15 alcatra
#> 3 alcatra_Mat_15 alcatra
#> 4 alcatra_Mat_20 alcatra
#> 5 alcatra_Mat_25 alcatra
#> 6 picanha_Mat_20 picanha
#> 7 picanha_Mat_25 picanha
Solution 2:[2]
You can use the following code:
library(dplyr)
df %>%
mutate(v2 = case_when(grepl("alcatra", v1) ~ "alcatra",
grepl("picanha", v1) ~ "picanha"))
Output:
v1 v2
1 aquiles_alcatra_Mat_15 alcatra
2 aquiles_alcatra_Mat_15 alcatra
3 alcatra_Mat_15 alcatra
4 alcatra_Mat_20 alcatra
5 alcatra_Mat_25 alcatra
6 picanha_Mat_20 picanha
7 picanha_Mat_25 picanha
Data
df <- data.frame(v1 = c("aquiles_alcatra_Mat_15", "aquiles_alcatra_Mat_15", "alcatra_Mat_15", "alcatra_Mat_20", "alcatra_Mat_25", "picanha_Mat_20", "picanha_Mat_25"),
v2 = c("picanha", "picanha", "picanha", "picanha", "picanha", "picanha", "picanha"))
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | PaulS |
| Solution 2 | Quinten |
