'Use of Cases with Where clause in MySQL query
I need to join the tables as per the where clause, basically I have a table of feeds structure is similar to the below, I have only mentioned the necessary columns as there are large number of columns which are unnecessary to show here
feed_id | type_id | user_id | timestamp
I am using the below query to get the result now.
SELECT feed.*
FROM `phpfox_feed` feed
JOIN `phpfox_user` u ON u.user_id = feed.user_id
Left Join `phpfox_friend` f ON feed.user_id = f.user_id AND f.friend_user_id = 441
Left Join `phpfox_app` apps ON feed.app_id = apps.app_id
Where feed.feed_reference = 0
AND feed.type_id in ("forum","blog","event","news","video","pages_created")
In type_id it shows the result i.e: news, events, group, blog
So I want that if row have 'feed_type' = news then it join with the specific tables, similarly if row have 'feed_type' = group it join with other tables, for example I mention the case of news and groups below
Case News:
Join phpfox_news ON phpfox_news.feed_id = feed.feed_id
Join phpfox_news_cateogries
ON phpfox_news.cateogry_id = phpfox_news_cateogries.cateogry_id
Where phpfox_news_cateogries.category_name in ("sports","politics","party")
Case Group:
Join phpfox_group ON phpfox_group.feed_id = feed.feed_id
Where phpfox_group.category_name in ("sports","politics","party")
What I tried
I tried the below by using an example I mentioned in where I Stuck, but it's giving me an error
SELECT feed.*
FROM `phpfox_feed` feed
JOIN `phpfox_user` u ON u.user_id = feed.user_id
Left Join `phpfox_friend` f ON feed.user_id = f.user_id AND f.friend_user_id = 441
Left Join `phpfox_app` apps ON feed.app_id = apps.app_id
Where feed.feed_reference = 0
AND feed.type_id in ("forum","blog","event","news","video","pages_created")
AND
Case
When feed.type_id = "news"
Then Join phpfox_news ON phpfox_news.feed_id = feed.feed_id
Join phpfox_news_cateogries
ON phpfox_news.cateogry_id = phpfox_news_cateogries.cateogry_id
Where phpfox_news_cateogries.category_name in ("sports","politics","party")
When feed.type_id = "group"
Then Join phpfox_group ON phpfox_group.feed_id = feed.feed_id
Where phpfox_group.category_name in ("sports","politics","party")
End
Where I got stuck
What I found is a Cases in SQL query, but I found it only support with select or in join like below example shows which I follow for what I tried above
Select LNext.player As NextPlayer
From lineups As L
Left Join lineups As LNext
On LNext.BattingOrder Between 11 And 20
And LNext.BattingOrder = Case
When L.BattingOrder = 19 Then 11
Else L.BattingOrder + 1
End
Where L.battingOrder Between 11 And 20
Query
Can this sort of query can be use with the 'Cases' in MySQL?
How can I use the Case with where clause to achieve my result
Solution 1:[1]
Try joining the tables while adding the condition for the feed.type_id to be the appropriate type.
Instead of doing:
When feed.type_id = "news" Then Join phpfox_news ON phpfox_news.feed_id = feed.feed_id
Try:
Join phpfox_news ON phpfox_news.feed_id = feed.feed_id AND feed.type_id = "news"
So the query you are trying to run should be altered to:
SELECT feed.*
FROM `phpfox_feed` feed
JOIN `phpfox_user` u ON u.user_id = feed.user_id
Left Join `phpfox_friend` f ON feed.user_id = f.user_id AND f.friend_user_id = 441
Left Join `phpfox_app` apps ON feed.app_id = apps.app_id
Left Join phpfox_news ON phpfox_news.feed_id = feed.feed_id AND feed.type_id = "news"
Left Join phpfox_news_cateogries ON phpfox_news.cateogry_id = phpfox_news_cateogries.cateogry_id
AND phpfox_news_cateogries.category_name in ("sports","politics","party")
Left Join phpfox_group ON phpfox_group.feed_id = feed.feed_id AND feed.type_id = "group" AND phpfox_group.category_name in ("sports","politics","party")
Where feed.feed_reference = 0
AND feed.type_id in ("forum","blog","event","news","video","pages_created")
Solution 2:[2]
As per the guide lines mentioned by @hofan41 i used the below query to get results from two different joins
SELECT feed.*
FROM `phpfox_feed` feed
JOIN `phpfox_user` u ON u.user_id = feed.user_id
Left Join `phpfox_friend` f ON feed.user_id = f.user_id AND f.friend_user_id = 441
Left Join `phpfox_app` apps ON feed.app_id = apps.app_id
Left Join phpfox_news_items ON phpfox_news_items.item_id = feed.item_id AND feed.type_id = "news"
Left Join phpfox_news_feeds ON phpfox_news_feeds.feed_id = phpfox_news_items.feed_id
Left Join phpfox_news_categories ON phpfox_news_categories.category_id = phpfox_news_feeds.category_id
Left Join phpfox_pages ON phpfox_pages.page_id = feed.item_id AND feed.type_id = "pages_created"
LEFT JOIN phpfox_pages_type ON phpfox_pages_type.type_id = phpfox_pages.type_id
Where feed.feed_reference = 0
AND feed.type_id in ("forum","blog","event","news","video","pages_created") AND (phpfox_news_categories.category_name in ("Movies","music") OR phpfox_pages_type.name in ("Movies","music"))
ORDER BY `feed`.`item_id` ASC
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | |
| Solution 2 | mobi001 |
