'Use LinqKit PredicateBuilder for related model (EF Core)
I want to use LinqKit's PredicateBuilder and pass the predicate into .Any method for related model.
So I want to build a predicate:
var castCondition = PredicateBuilder.New<CastInfo>(true);
if (movies != null && movies.Length > 0)
{
castCondition = castCondition.And(c => movies.Contains(c.MovieId));
}
if (roleType > 0)
{
castCondition = castCondition.And(c => c.RoleId == roleType);
}
And then use it to filter model that has relation to model in predicate:
IQueryable<Name> result = _context.Name.AsExpandable().Where(n => n.CastInfo.Any(castCondition));
return await result.OrderBy(n => n.Name1).Take(25).ToListAsync();
But this causes a System.NotSupportedException: Could not parse expression 'n.CastInfo.Any(Convert(__castCondition_0, Func``2))': The given arguments did not match the expected arguments: Object of type 'System.Linq.Expressions.UnaryExpression' cannot be converted to type 'System.Linq.Expressions.LambdaExpression'.
I saw similar question and answer there suggests to use .Compile. Or one more question that build an extra predicate.
So I tried to use extra predicate
var tp = PredicateBuilder.New<Name>(true);
tp = tp.And(n => n.CastInfo.Any(castCondition.Compile()));
IQueryable<Name> result = _context.Name.AsExpandable().Where(tp);
Or use compile directly
IQueryable<Name> result = _context.Name.AsExpandable().Where(n => n.CastInfo.Any(castCondition.Compile()));
But I have an error about Compile: System.NotSupportedException: Could not parse expression 'n.CastInfo.Any(__Compile_0)'
So is it possible to convert the result from PredicateBuilder to pass into Any?
Note: I was able to build the desired behavior combining expressions, but I don't like that I need extra variables.
System.Linq.Expressions.Expression<Func<CastInfo,bool>> castExpression = (c => true);
if (movies != null && movies.Length > 0)
{
castExpression = (c => movies.Contains(c.MovieId));
}
if (roleType > 0)
{
var existingExpression = castExpression;
castExpression = c => existingExpression.Invoke(c) && c.RoleId == roleType;
}
IQueryable<Name> result = _context.Name.AsExpandable().Where(n => n.CastInfo.Any(castExpression.Compile()));
return await result.OrderBy(n => n.Name1).Take(25).ToListAsync();
So I assume I just miss something about builder.
Update about versions: I use dotnet core 2.0 and LinqKit.Microsoft.EntityFrameworkCore 1.1.10
Solution 1:[1]
It may not be exactly related to the original question, but considering the following model :
public Class Music
{
public int Id { get; set; }
public List<Genre> Genres { get; set; }
}
public Class Genre
{
public int Id { get; set; }
public string Title { get; set; }
}
List<string> genresToFind = new() {"Pop", "Rap", "Classical"};
If you are trying to find all Musics that their genres exist in genresToFind list, here's what you can do:
Create PredicateBuilder expressions chain on Genre model :
var pre = PredicateBuilder.New<Genre>();
foreach (var genre in genresToFind)
{
pre = pre.Or(g => g.Title.Contains(genre));
}
Then execute your query like this :
var result = await _db.Musics.AsExpandable()
.Where(m => m.Genres
.Any(g => pre.ToExpression().Invoke(g)))
.ToListAsync();
ToExpression() is a generic extension method that we've created to convert ExpressionStarter<Genre> type to Expression<Func<Genre, bool>> :
public static class ExpressionExtensions
{
public static Expression<Func<T, bool>> ToExpression<T> (this
ExpressionStarter<T> exp) => exp;
}
Also, you'll need LinqKit.Microsoft.EntityFrameworkCore package for efcore.
Solution 2:[2]
Delete the type="submit" attribute. This attribute let's the form send.
<h3> Backtest ID: {{ backtestID }} </h3>
<div class="row">
<div class="col-md-1" >
<form method="post">
<button class="btn btn-success"
formaction="{{ url_for('results.save_backtest', id=backtestID) }}">Save</button>
</form>
</div>
<div class="col-md-1" >
<form method="post">
<button class="btn btn-info"
formaction="{{ url_for('results.rerun_backtest', id=backtestID) }}">Run</button>
</form>
</div>
</div>
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Mehran Rasa |
| Solution 2 | Aaron Junker |
