'Undefined variable in function php [closed]
I have the following php code below, it keeps throwing out a undefined variable $checked once the plugin is activated.
How do I use function in function correctly?
Solution 1:[1]
write this :
function sanitize_check($check = null)
insted:
function sanitize_check($check)
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | amirhosein hadi |