'Typescript subset of enum
In Typescript, I have an enum like
export enum CarBrands {
Toyota = "TOYOTA"
Ford = "FORD"
.....
}
I would like to create a subset of this enum like this but cannot seem to do it
enum JapaneseCars {
CarBrands.Toyota
}
or create an object with a subset
const JapaneseCars = {
Carbrands.Toyota
}
Is there anyway i can create an object or enum that uses that values from another existing enum?
I cannot change the CarBrands enum to be some other data type
Solution 1:[1]
You can create a type and const combination that will behave like an enum that is the subset of another enum.
Drawback: this solution forces you to have any enum's key match their value (or I have not found a solution that handles that case yet)
// Given an enum
export enum CarBrand {
TOYOTA = 'TOYOTA',
FORD = 'FORD',
PEUGEOT = 'PEUGEOT',
RENAULT = 'RENAULT'
}
// We can create the type of the subset
export type FrenchCarBrand = Extract<CarBrand, CarBrand.PEUGEOT | CarBrand.RENAULT>;
// And the const that goes with it
export const FrenchCarBrand: Readonly<Record<FrenchCarBrand, FrenchCarBrand>> = {
[CarBrand.PEUGEOT]: CarBrand.PEUGEOT,
[CarBrand.RENAULT]: CarBrand.RENAULT
};
// With that you can :
// assign a CarBrand to a FrenchCarBrand ...
const a: FrenchCarBrand = CarBrand.RENAULT;
// ... as long as the CarBrand is in the type
const a_invalid: FrenchCarBrand = CarBrand.TOYOTA; // Type 'CarBrand.TOYOTA' is not assignable to type 'FrenchCarBrand'.
// assign a FrenchCarBrand to a CarBrand ...
const b: CarBrand = FrenchCarBrand.PEUGEOT;
// ... as long as the key exists
const b_invalid: CarBrand = FrenchCarBrand.TOYOTA; // Property 'TOYOTA' does not exist on type 'Readonly<Record<FrenchCarBrand, FrenchCarBrand>>'
// You cannot reassign the value of a FrenchCarBrand ...
FrenchCarBrand.PEUGEOT = CarBrand.RENAULT; // Cannot assign to 'PEUGEOT' because it is a read-only property.
// ... just like you cannot reassign the value of an enum
CarBrand.TOYOTA = 'MAZDA'; // Cannot assign to 'TOYOTA' because it is a read-only property.
If you want to map an unknown value of type CarBrand to a value of type FrenchCarBrand, it will not work though :
declare const brand: CarBrand;
const frenchBrand: FrenchCarBrand = brand; // Type 'CarBrand' is not assignable to type 'FrenchCarBrand'
// You can use the `as` keyword but it will hide bugs, so I do not recommend at all.
const frenchBrandNoError: FrenchCarBrand = brand as FrenchCarBrand; // No error, but a possible bug in your application.
For that you need a type guard :
export const isFrenchCarBrand = (brand: CarBrand): brand is FrenchCarBrand => {
return brand in FrenchCarBrand;
}
It will allow you to decide what to do in case you encounter an unwanted value
if (isFrenchCarBrand(brand)) {
// You can safely assume that `brand` is a `FrendCarBrand`
} else {
// `brand` is definitely not a `FrendCarBrand`
}
I have made a TypeScript Playground that show all this code with type checking in action
Solution 2:[2]
You could make a variable for every single enum member, which would be tedious if you have a lot of enum members but it would look like this.
export enum CarBrands {
Toyota = "TOYOTA",
Ford = "FORD"
}
const Toyota = CarBrands.Toyota;
console.log("The Supra is made by", Toyota)
or you can use a simple method
class JapaneseCar {
make: string;
// Additional Methods / Properties
setMake(brand:CarBrands){
this.make = brand;
}
}
const ToyotaSupra = new JapaneseCar();
ToyotaSupra.setMake(CarBrands.Toyota);
console.log(ToyotaSupra.make)
Solution 3:[3]
I think you want to make an indexed object with optional values:
enum CarBrand {
TOYOTA = "TOYOTA",
FORD = "FORD"
}
type CarsSubset = {
[key in CarBrand]?: boolean
}
const JapaneseCars: CarsSubset = {
TOYOTA: true,
}
For this particular example it may be clearer to just use Set<CarBrand> though:
const JapaneseCars = new Set<CarBrand>([CarBrand.TOYOTA]);
Solution 4:[4]
I think you're looking for something like this -
export enum CarBrands {
Toyota = "TOYOTA",
Ford = "FORD"
}
type JapaneseCars = CarBrands.Toyota;
const car: JapaneseCars;
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Magador |
| Solution 2 | |
| Solution 3 | Nacho Coloma |
| Solution 4 | gatsbyz |
