Typescript - inherit duplicated constructor in all derived classes using generics

Question

I have some classes that have identical constructor (partial field assignment). I don't want to write a lot of duplicated constructor so I come up with:

class Base<T> {
    constructor(properties: Partial<T> = {}) {
        Object.assign(this, properties);
    }
}

class Child {
    data: number[] = []

    ownMethod() {
        // ...
    }
}

var test = new Base<Child>({data: [1,2,3]}); // Base: {"data": [1,2,3]}

This works, but the instances created are all Base instead of Child. Is there a way to make each derived class construct itself instead of Base?

class Child extends Base<Child> {
    data: number[] = []

    ownMethod() {
        // ...
    }
}

var test = new Child({data: [1,2,3]}); // Child: {"data": []}

This does not work.

class Child extends Base<Child> {
    data!: number[]
    isOpen: boolean

    ownMethod() {
        // ...
    }
}

var test = new Child({data: [1,2,3]}); // Child: {"data": [1,2,3]}

This works partially, that Partial does not make sense as if you are not specifying a field it will not be in the object (e.g. isOpen)