'top 1 case in select statement on TSQL

I am having problem on this query. How can I fix this:

select (select case top 1 STATUS 
       when 'Inprocess' then 'Processing' 
       when 'Inworkbin' then 'Waiting In Draft' 
       end 
    from ICS_EMAIL_CONNECTIONS_TRX A    
    where A.SESSIONID = B.SESSIONID 
    and STATUS <> 'Completed'
    order by A.CREATE_DATE desc) as LAST_STATUS

I am getting this error:

Incorrect syntax near the keyword 'top'.

Any suggestions?

sqltsqlcasetop-n


Solution 1:[1]

You don't need the nested select.

select top 1 case STATUS 
             when 'Inprocess' then 'Processing' 
             when 'Inworkbin' then 'Waiting In Draft' 
             end LAST_STATUS
from ICS_EMAIL_CONNECTIONS_TRX A    
where A.SESSIONID = B.SESSIONID 
and STATUS <> 'Completed'
order by A.CREATE_DATE desc;

Although this can return 0 rows whereas your original form with the TOP 1 written properly will always return one row, even if the value is NULL.

Solution 2:[2]

select (select top 1 (case STATUS 
   when 'Inprocess' then 'Processing' 
   when 'Inworkbin' then 'Waiting In Draft' 
   end) 
from ICS_EMAIL_CONNECTIONS_TRX A    
where A.SESSIONID = B.SESSIONID 
and STATUS <> 'Completed'
order by A.CREATE_DATE desc) as LAST_STATUS

Solution 3:[3]

corrrect the case and top keyword

select (select top 1 case STATUS 
       when 'Inprocess' then 'Processing' 
       when 'Inworkbin' then 'Waiting In Draft' 
       end 
    from ICS_EMAIL_CONNECTIONS_TRX A    
    where A.SESSIONID = B.SESSIONID 
    and STATUS <> 'Completed'
    order by A.CREATE_DATE desc) as LAST_STATUS

Solution 4:[4]

select top 1 * from (select case STATUS 
       when 'Inprocess' then 'Processing' 
       when 'Inworkbin' then 'Waiting In Draft' 
       end 
    from ICS_EMAIL_CONNECTIONS_TRX A    
    where A.SESSIONID = B.SESSIONID 
    and STATUS <> 'Completed'
    order by A.CREATE_DATE desc) as LAST_STATUS

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source
Solution 1 RichardTheKiwi
Solution 2 AgeDeO
Solution 3 Sandeep Kumar
Solution 4 Anvesh

Related Questions