'Thousand separator in flutter
Is there a way to make a thousand separator when typing numbers in a TextFormField in flutter?
This is my TextFormField
child: TextFormField(
decoration: InputDecoration(
border: const OutlineInputBorder()),
keyboardType: TextInputType.number,
),
Solution 1:[1]
There isn't anything built into Flutter to handle this. You will have to roll with your own customized text formatter. (Derived from this answer.)
import 'package:flutter/services.dart';
class ThousandsSeparatorInputFormatter extends TextInputFormatter {
static const separator = ','; // Change this to '.' for other locales
@override
TextEditingValue formatEditUpdate(
TextEditingValue oldValue, TextEditingValue newValue) {
// Short-circuit if the new value is empty
if (newValue.text.length == 0) {
return newValue.copyWith(text: '');
}
// Handle "deletion" of separator character
String oldValueText = oldValue.text.replaceAll(separator, '');
String newValueText = newValue.text.replaceAll(separator, '');
if (oldValue.text.endsWith(separator) &&
oldValue.text.length == newValue.text.length + 1) {
newValueText = newValueText.substring(0, newValueText.length - 1);
}
// Only process if the old value and new value are different
if (oldValueText != newValueText) {
int selectionIndex =
newValue.text.length - newValue.selection.extentOffset;
final chars = newValueText.split('');
String newString = '';
for (int i = chars.length - 1; i >= 0; i--) {
if ((chars.length - 1 - i) % 3 == 0 && i != chars.length - 1)
newString = separator + newString;
newString = chars[i] + newString;
}
return TextEditingValue(
text: newString.toString(),
selection: TextSelection.collapsed(
offset: newString.length - selectionIndex,
),
);
}
// If the new value and old value are the same, just return as-is
return newValue;
}
}
Usage:
TextField(
decoration: InputDecoration(
border: const OutlineInputBorder(),
),
keyboardType: TextInputType.number,
inputFormatters: [ThousandsSeparatorInputFormatter()],
),
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Abion47 |
