'Syntax of `sep =` as separator
I would like to understand how is the syntax of the command sep =. Below, I report an example code:
library(ggpmisc)
library(ggplot2)
formula <- y ~ x + I(x^2)
ggplot(cars, aes(speed, dist)) +
geom_point() +
stat_fit_deviations(formula = formula, colour = "red") +
stat_poly_line(formula = formula) +
stat_poly_eq(aes(label = paste(stat(eq.label), stat(adj.rr.label), sep = "*\", \"*")),
formula = formula)
I understand that sep = "*\", \"*" is aiming to add a comma between eq.label and adj.rr.label. There is no reference on the guide of stat_poly_eq, I would like to understand the meaning of "*\" and \"*", perhaps learning something more to change this configuration.
Solution 1:[1]
The labels you create in stat_poly_eq are character strings. They are parsed into expressions, which in turn are converted into plotmath symbols. You can get a feel for how this works if you do:
plot(1:10, type = 'n')
text(5, 5, label = expression(paste(y~`=`~3*italic(x)^2*", "*R^2)))
All the sep is doing in your case is providing a separating comma and space between the formula and the R squared. You can change this to anything you like as long as it parses correctly to a valid plotmath expression:
formula <- y ~ x + I(x^2)
ggplot(cars, aes(speed, dist)) +
geom_point() +
stat_fit_deviations(formula = formula, colour = "red") +
stat_poly_line(formula = formula) +
stat_poly_eq(aes(label = paste(stat(eq.label), stat(adj.rr.label),
sep = "*\" is the formula, and the R squared is \"*")),
formula = formula)
See ?plotmath to find out all the things your can do with plotmath expressions
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Allan Cameron |


